What are the solutions to the equation x^2+18x+32=0 ?

The solutions to the equation x^2+18x+32=0 are x=-2,x=-16

Find the zeros of x^2+18x+32=0

The zeros of x^2+18x+32=0 are x=-2,x=-16

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x^{2} + 18 x + 32 = 0

x = - 2, x = - 16

Solution steps

x^{2} + 18 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 32}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 32 = 14

x_{1, 2} = \frac{- 18 \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 14}{2 \cdot 1}, x_{2} = \frac{- 18 - 14}{2 \cdot 1}

x = \frac{- 18 + 14}{2 \cdot 1} : - 2

x = \frac{- 18 - 14}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

x = - 2, x = - 16

x^{2} - 19 = - 9 x - 9

x, x^{2} + y^{2} + z^{2} = 9

(2 x + 3) (3 x - 1) = - 4

c, E = m c^{2}

4 (x + 3)^{2} - 38 = - 22

What are the solutions to the equation x^2+18x+32=0 ?
The solutions to the equation x^2+18x+32=0 are x=-2,x=-16
Find the zeros of x^2+18x+32=0
The zeros of x^2+18x+32=0 are x=-2,x=-16