What are the solutions to the equation 12-3x^2=0 ?

The solutions to the equation 12-3x^2=0 are x=2,x=-2

Find the zeros of 12-3x^2=0

The zeros of 12-3x^2=0 are x=2,x=-2

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12 - 3 x^{2} = 0

x = 2, x = - 2

Solution steps

12 - 3 x^{2} = 0

Move

12

to the right side

- 3 x^{2} = - 12

Divide both sides by

- 3

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

x, x^{2} = y^{3}

x, 4 x^{2} + 3 x y - 4 y^{2} - 12 x - 18 y + 4 = 0

3 (x - 8)^{2} - 34 = - 7

x^{2} + 8 x + 6

x^{2} - 2 x - 15 = 0

What are the solutions to the equation 12-3x^2=0 ?
The solutions to the equation 12-3x^2=0 are x=2,x=-2
Find the zeros of 12-3x^2=0
The zeros of 12-3x^2=0 are x=2,x=-2