What are the solutions to the equation 4(x+7)^2-49=-13 ?

The solutions to the equation 4(x+7)^2-49=-13 are x=-4,x=-10

Find the zeros of 4(x+7)^2-49=-13

The zeros of 4(x+7)^2-49=-13 are x=-4,x=-10

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4 (x + 7)^{2} - 49 = - 13

x = - 4, x = - 10

Solution steps

4 (x + 7)^{2} - 49 = - 13

Move

49

to the right side

4 (x + 7)^{2} = 36

Divide both sides by

4

(x + 7)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = 9 : x = - 4

Solve

x + 7 = - 9 : x = - 10

The solutions to the quadratic equation are:

x = - 4, x = - 10

x^{2} - 6 x + 9 = 256

7 x = 15 - 30 x^{2}

x^{2} = 7 x - 12

4 (x + 7)^{2} + 17 = 33

x^{2} - 2 x - 168 = 0

What are the solutions to the equation 4(x+7)^2-49=-13 ?
The solutions to the equation 4(x+7)^2-49=-13 are x=-4,x=-10
Find the zeros of 4(x+7)^2-49=-13
The zeros of 4(x+7)^2-49=-13 are x=-4,x=-10