What are the solutions to the equation 5x^2+3x-3=0 ?

The solutions to the equation 5x^2+3x-3=0 are x=(-3+sqrt(69))/(10),x=(-3-sqrt(69))/(10)

Find the zeros of 5x^2+3x-3=0

The zeros of 5x^2+3x-3=0 are x=(-3+sqrt(69))/(10),x=(-3-sqrt(69))/(10)

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5 x^{2} + 3 x - 3 = 0

x = \frac{- 3 + 69}{10}, x = \frac{- 3 - 69}{10}

Solution steps

5 x^{2} + 3 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 5 ( - 3 )}{2 \cdot 5}

3^{2} - 4 \cdot 5 (- 3) = 69

x_{1, 2} = \frac{- 3 \pm 69}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 3 + 69}{2 \cdot 5}, x_{2} = \frac{- 3 - 69}{2 \cdot 5}

x = \frac{- 3 + 69}{2 \cdot 5} : \frac{- 3 + 69}{10}

x = \frac{- 3 - 69}{2 \cdot 5} : \frac{- 3 - 69}{10}

The solutions to the quadratic equation are:

x = \frac{- 3 + 69}{10}, x = \frac{- 3 - 69}{10}

- 6 \leq \frac{3 x + 17}{7} < 7

64 x^{2} + 80 x + 25

x = ln (9)

- 9 x \geq 18

- \frac{4}{- 5}

What are the solutions to the equation 5x^2+3x-3=0 ?
The solutions to the equation 5x^2+3x-3=0 are x=(-3+sqrt(69))/(10),x=(-3-sqrt(69))/(10)
Find the zeros of 5x^2+3x-3=0
The zeros of 5x^2+3x-3=0 are x=(-3+sqrt(69))/(10),x=(-3-sqrt(69))/(10)