What are the solutions to the equation x^2+118=20x ?

The solutions to the equation x^2+118=20x are x=10+3sqrt(2)i,x=10-3sqrt(2)i

Find the zeros of x^2+118=20x

The zeros of x^2+118=20x are x=10+3sqrt(2)i,x=10-3sqrt(2)i

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x^{2} + 118 = 20 x

x = 10 + 32 i, x = 10 - 32 i

Solution steps

x^{2} + 118 = 20 x

Move

20 x

to the left side

x^{2} + 118 - 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 20 x + 118 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 118}{2 \cdot 1}

Simplify

(- 20)^{2} - 4 \cdot 1 \cdot 118 : 62 i

x_{1, 2} = \frac{- ( - 20 ) \pm 6 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 6 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 6 2 i}{2 \cdot 1}

x = \frac{- ( - 20 ) + 6 2 i}{2 \cdot 1} : 10 + 32 i

x = \frac{- ( - 20 ) - 6 2 i}{2 \cdot 1} : 10 - 32 i

The solutions to the quadratic equation are:

x = 10 + 32 i, x = 10 - 32 i

a x^{2} + b x + c

x^{2} + 10 x = - 16

x, x^{2} + y^{2} + z^{2} = 25

m x^{2} - n x + 1 = 0

a^{2} + 3 a - \frac{1}{2} = 0

What are the solutions to the equation x^2+118=20x ?
The solutions to the equation x^2+118=20x are x=10+3sqrt(2)i,x=10-3sqrt(2)i
Find the zeros of x^2+118=20x
The zeros of x^2+118=20x are x=10+3sqrt(2)i,x=10-3sqrt(2)i