What are the solutions to the equation 3x-6x^2=2x^2-5x ?

The solutions to the equation 3x-6x^2=2x^2-5x are x=0,x=1

Find the zeros of 3x-6x^2=2x^2-5x

The zeros of 3x-6x^2=2x^2-5x are x=0,x=1

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3 x - 6 x^{2} = 2 x^{2} - 5 x

x = 0, x = 1

Solution steps

3 x - 6 x^{2} = 2 x^{2} - 5 x

Move

5 x

to the left side

- 6 x^{2} + 8 x = 2 x^{2}

Move

2 x^{2}

to the left side

- 8 x^{2} + 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 8 ) \cdot 0}{2 ( - 8 )}

8^{2} - 4 (- 8) \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- 8 + 8}{2 ( - 8 )}, x_{2} = \frac{- 8 - 8}{2 ( - 8 )}

x = \frac{- 8 + 8}{2 ( - 8 )} : 0

x = \frac{- 8 - 8}{2 ( - 8 )} : 1

The solutions to the quadratic equation are:

x = 0, x = 1

x^{2} + 6 x + 3

x^{2} - 3 x - 11 = 0

x^{2} + 20 x + 12 = 0

x^{2} + 16 = - 10 x

m^{2} + m - 6 = 0

What are the solutions to the equation 3x-6x^2=2x^2-5x ?
The solutions to the equation 3x-6x^2=2x^2-5x are x=0,x=1
Find the zeros of 3x-6x^2=2x^2-5x
The zeros of 3x-6x^2=2x^2-5x are x=0,x=1