What are the solutions to the equation x^2-4x-15=0 ?

The solutions to the equation x^2-4x-15=0 are x=2+sqrt(19),x=2-sqrt(19)

Find the zeros of x^2-4x-15=0

The zeros of x^2-4x-15=0 are x=2+sqrt(19),x=2-sqrt(19)

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x^{2} - 4 x - 15 = 0

x = 2 + 19, x = 2 - 19

Decimal Notation

x = 6.35889 \dots, x = - 2.35889 \dots

Solution steps

x^{2} - 4 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 15) = 219

x_{1, 2} = \frac{- ( - 4 ) \pm 2 19}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 19}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 19}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 19}{2 \cdot 1} : 2 + 19

x = \frac{- ( - 4 ) - 2 19}{2 \cdot 1} : 2 - 19

The solutions to the quadratic equation are:

x = 2 + 19, x = 2 - 19

5 x^{2} - 10 x - 13 = 9 x - 9

r, A = 2 π r^{2} + 2 π r h

(x - 7)^{2} = 11

4 x^{2} - 10 = 4 x - 7

y^{2} - 2 y

What are the solutions to the equation x^2-4x-15=0 ?
The solutions to the equation x^2-4x-15=0 are x=2+sqrt(19),x=2-sqrt(19)
Find the zeros of x^2-4x-15=0
The zeros of x^2-4x-15=0 are x=2+sqrt(19),x=2-sqrt(19)