What are the solutions to the equation -36+(x-12)^2=24 ?

The solutions to the equation -36+(x-12)^2=24 are x=2sqrt(15)+12,x=-2sqrt(15)+12

Find the zeros of -36+(x-12)^2=24

The zeros of -36+(x-12)^2=24 are x=2sqrt(15)+12,x=-2sqrt(15)+12

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- 36 + (x - 12)^{2} = 24

x = 215 + 12, x = - 215 + 12

Decimal Notation

x = 19.74596 \dots, x = 4.25403 \dots

Solution steps

- 36 + (x - 12)^{2} = 24

Move

36

to the right side

(x - 12)^{2} = 60

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 12 = 60 : x = 215 + 12

Solve

x - 12 = - 60 : x = - 215 + 12

The solutions to the quadratic equation are:

x = 215 + 12, x = - 215 + 12

a, a^{2} = b^{2}

x^{2} + 5 x - 12 = 0

(x - 2)^{2} - (2 x + 3)^{2} = - 80

2 x^{2} + 4 = - 5 x + 1

0 = x^{2} + 1

What are the solutions to the equation -36+(x-12)^2=24 ?
The solutions to the equation -36+(x-12)^2=24 are x=2sqrt(15)+12,x=-2sqrt(15)+12
Find the zeros of -36+(x-12)^2=24
The zeros of -36+(x-12)^2=24 are x=2sqrt(15)+12,x=-2sqrt(15)+12