What are the solutions to the equation 25x^2+50x+26=0 ?

The solutions to the equation 25x^2+50x+26=0 are x=-1+i 1/5 ,x=-1-i 1/5

Find the zeros of 25x^2+50x+26=0

The zeros of 25x^2+50x+26=0 are x=-1+i 1/5 ,x=-1-i 1/5

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25 x^{2} + 50 x + 26 = 0

x = - 1 + i \frac{1}{5}, x = - 1 - i \frac{1}{5}

Solution steps

25 x^{2} + 50 x + 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 \cdot 25 \cdot 26}{2 \cdot 25}

Simplify

5 0^{2} - 4 \cdot 25 \cdot 26 : 10 i

x_{1, 2} = \frac{- 50 \pm 10 i}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- 50 + 10 i}{2 \cdot 25}, x_{2} = \frac{- 50 - 10 i}{2 \cdot 25}

x = \frac{- 50 + 10 i}{2 \cdot 25} : - 1 + i \frac{1}{5}

x = \frac{- 50 - 10 i}{2 \cdot 25} : - 1 - i \frac{1}{5}

The solutions to the quadratic equation are:

x = - 1 + i \frac{1}{5}, x = - 1 - i \frac{1}{5}

x^{2} - 51 = 14 x

x, f = x^{2} y^{3}

4 x^{2} + 27 x + 3 = 10

12 x^{2} - 216 x + 665 = 0

x^{2} - 59 = 8 x

What are the solutions to the equation 25x^2+50x+26=0 ?
The solutions to the equation 25x^2+50x+26=0 are x=-1+i 1/5 ,x=-1-i 1/5
Find the zeros of 25x^2+50x+26=0
The zeros of 25x^2+50x+26=0 are x=-1+i 1/5 ,x=-1-i 1/5