What are the solutions to the equation -7x^2-2=-10x ?

The solutions to the equation -7x^2-2=-10x are x=(5-sqrt(11))/7 ,x=(5+sqrt(11))/7

Find the zeros of -7x^2-2=-10x

The zeros of -7x^2-2=-10x are x=(5-sqrt(11))/7 ,x=(5+sqrt(11))/7

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- 7 x^{2} - 2 = - 10 x

x = \frac{5 - 11}{7}, x = \frac{5 + 11}{7}

Decimal

x = 0.24048 \dots, x = 1.18808 \dots

Solution steps

- 7 x^{2} - 2 = - 10 x

Move

10 x

to the left side

- 7 x^{2} - 2 + 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 7 x^{2} + 10 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 7 ) ( - 2 )}{2 ( - 7 )}

1 0^{2} - 4 (- 7) (- 2) = 211

x_{1, 2} = \frac{- 10 \pm 2 11}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- 10 + 2 11}{2 ( - 7 )}, x_{2} = \frac{- 10 - 2 11}{2 ( - 7 )}

x = \frac{- 10 + 2 11}{2 ( - 7 )} : \frac{5 - 11}{7}

x = \frac{- 10 - 2 11}{2 ( - 7 )} : \frac{5 + 11}{7}

The solutions to the quadratic equation are:

x = \frac{5 - 11}{7}, x = \frac{5 + 11}{7}

x^{2} - 18 x

3 p^{2} + 9 p = - 6

2 (x^{2} + 2) - 6 = 6

x^{2} + 4 x = - 20

x^{2} + x = 56

What are the solutions to the equation -7x^2-2=-10x ?
The solutions to the equation -7x^2-2=-10x are x=(5-sqrt(11))/7 ,x=(5+sqrt(11))/7
Find the zeros of -7x^2-2=-10x
The zeros of -7x^2-2=-10x are x=(5-sqrt(11))/7 ,x=(5+sqrt(11))/7