What are the solutions to the equation 3x^2-24x=-12 ?

The solutions to the equation 3x^2-24x=-12 are x=2(2+sqrt(3)),x=2(2-sqrt(3))

Find the zeros of 3x^2-24x=-12

The zeros of 3x^2-24x=-12 are x=2(2+sqrt(3)),x=2(2-sqrt(3))

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3 x^{2} - 24 x = - 12

x = 2 (2 + 3), x = 2 (2 - 3)

Decimal Notation

x = 7.46410 \dots, x = 0.53589 \dots

Solution steps

3 x^{2} - 24 x = - 12

Move

12

to the left side

3 x^{2} - 24 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

(- 24)^{2} - 4 \cdot 3 \cdot 12 = 123

x_{1, 2} = \frac{- ( - 24 ) \pm 12 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 12 3}{2 \cdot 3}, x_{2} = \frac{- ( - 24 ) - 12 3}{2 \cdot 3}

x = \frac{- ( - 24 ) + 12 3}{2 \cdot 3} : 2 (2 + 3)

x = \frac{- ( - 24 ) - 12 3}{2 \cdot 3} : 2 (2 - 3)

The solutions to the quadratic equation are:

x = 2 (2 + 3), x = 2 (2 - 3)

x^{2} + 14 x + 49 = 100

16 x^{2} + 16 x + 5 = 0

x^{2} + x - 132 = 0

(x + 8)^{2} = 25

4 x^{2} + 4 x = - 5

What are the solutions to the equation 3x^2-24x=-12 ?
The solutions to the equation 3x^2-24x=-12 are x=2(2+sqrt(3)),x=2(2-sqrt(3))
Find the zeros of 3x^2-24x=-12
The zeros of 3x^2-24x=-12 are x=2(2+sqrt(3)),x=2(2-sqrt(3))