What is (2i-1)^2{4/(1-i)+(2-i)/(1+i)} ?

The solution to (2i-1)^2{4/(1-i)+(2-i)/(1+i)} is -11/2-23/2 i

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simplify (2i-1)^2{4/(1-i)+(2-i)/(1+i)}

simplify

(2 i - 1)^{2} {\frac{4}{1 - i} + \frac{2 - i}{1 + i}}

- \frac{11}{2} - \frac{23}{2} i

Solution steps

(2 i - 1)^{2} (\frac{4}{1 - i} + \frac{2 - i}{1 + i})

Expand

(2 i - 1)^{2} : - 4 i - 3

= (- 4 i - 3) (\frac{4}{1 - i} + \frac{2 - i}{1 + i})

Apply FOIL method

(- 4 i - 3) (\frac{4}{1 - i} + \frac{2 - i}{1 + i}) : - \frac{11}{2} - \frac{23}{2} i

= - \frac{11}{2} - \frac{23}{2} i

y^{2} + y = 20

4 a^{2} - 25 b^{2}

\frac{8}{5} \div (\frac{3}{4} \div \frac{3}{8})

\frac{2 b - 3}{7} - \frac{b}{2} = \frac{b + 3}{14}

618

What is (2i-1)^2{4/(1-i)+(2-i)/(1+i)} ?
The solution to (2i-1)^2{4/(1-i)+(2-i)/(1+i)} is -11/2-23/2 i