What are the solutions to the equation 3x^2-27x-18=0 ?

The solutions to the equation 3x^2-27x-18=0 are x=(9+sqrt(105))/2 ,x=(9-sqrt(105))/2

Find the zeros of 3x^2-27x-18=0

The zeros of 3x^2-27x-18=0 are x=(9+sqrt(105))/2 ,x=(9-sqrt(105))/2

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3 x^{2} - 27 x - 18 = 0

x = \frac{9 + 105}{2}, x = \frac{9 - 105}{2}

Decimal Notation

x = 9.62347 \dots, x = - 0.62347 \dots

Solution steps

3 x^{2} - 27 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 3 ( - 18 )}{2 \cdot 3}

(- 27)^{2} - 4 \cdot 3 (- 18) = 3105

x_{1, 2} = \frac{- ( - 27 ) \pm 3 105}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 27 ) + 3 105}{2 \cdot 3}, x_{2} = \frac{- ( - 27 ) - 3 105}{2 \cdot 3}

x = \frac{- ( - 27 ) + 3 105}{2 \cdot 3} : \frac{9 + 105}{2}

x = \frac{- ( - 27 ) - 3 105}{2 \cdot 3} : \frac{9 - 105}{2}

The solutions to the quadratic equation are:

x = \frac{9 + 105}{2}, x = \frac{9 - 105}{2}

2 x^{2} + 4 x + 1

- 4 x^{2} + 4 x - 1 = 0

x^{2} - 28 x + 196 = 64

x^{2} + 8^{2} = 1 7^{2}

5 x^{2} + 10 x + 2

What are the solutions to the equation 3x^2-27x-18=0 ?
The solutions to the equation 3x^2-27x-18=0 are x=(9+sqrt(105))/2 ,x=(9-sqrt(105))/2
Find the zeros of 3x^2-27x-18=0
The zeros of 3x^2-27x-18=0 are x=(9+sqrt(105))/2 ,x=(9-sqrt(105))/2