What are the solutions to the equation x^2-2x+193=0 ?

The solutions to the equation x^2-2x+193=0 are x=1+8sqrt(3)i,x=1-8sqrt(3)i

Find the zeros of x^2-2x+193=0

The zeros of x^2-2x+193=0 are x=1+8sqrt(3)i,x=1-8sqrt(3)i

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x^{2} - 2 x + 193 = 0

x = 1 + 83 i, x = 1 - 83 i

Solution steps

x^{2} - 2 x + 193 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 193}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 193 : 163 i

x_{1, 2} = \frac{- ( - 2 ) \pm 16 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 16 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 16 3 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 16 3 i}{2 \cdot 1} : 1 + 83 i

x = \frac{- ( - 2 ) - 16 3 i}{2 \cdot 1} : 1 - 83 i

The solutions to the quadratic equation are:

x = 1 + 83 i, x = 1 - 83 i

2 x^{2} - 4 = 28

3 x^{2} - 5 x = - 7

2 x^{2} = 2 x

9 x^{2} = 12 x - 4

X^{2} + 11 X - 60 = 0

What are the solutions to the equation x^2-2x+193=0 ?
The solutions to the equation x^2-2x+193=0 are x=1+8sqrt(3)i,x=1-8sqrt(3)i
Find the zeros of x^2-2x+193=0
The zeros of x^2-2x+193=0 are x=1+8sqrt(3)i,x=1-8sqrt(3)i