What are the solutions to the equation 4-2a^2=-7 ?

The solutions to the equation 4-2a^2=-7 are a=sqrt(11/2),a=-sqrt(11/2)

Find the zeros of 4-2a^2=-7

The zeros of 4-2a^2=-7 are a=sqrt(11/2),a=-sqrt(11/2)

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4 - 2 a^{2} = - 7

a = \frac{11}{2}, a = - \frac{11}{2}

Decimal Notation

a = 2.34520 \dots, a = - 2.34520 \dots

Solution steps

4 - 2 a^{2} = - 7

Move

4

to the right side

- 2 a^{2} = - 11

Divide both sides by

- 2

a^{2} = \frac{11}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = \frac{11}{2}, a = - \frac{11}{2}

x, 8 x^{2} - 6 y^{2} - 16 x + 24 y - 16 = 0

(4 x - 3) (5 x - 4) = 0

x^{2} - 18 x = - 31

x^{2} + 10 x + 22 = 13

2 x = 1 - 3 x^{2}

What are the solutions to the equation 4-2a^2=-7 ?
The solutions to the equation 4-2a^2=-7 are a=sqrt(11/2),a=-sqrt(11/2)
Find the zeros of 4-2a^2=-7
The zeros of 4-2a^2=-7 are a=sqrt(11/2),a=-sqrt(11/2)