What are the solutions to the equation x^2-26x+169=49 ?

The solutions to the equation x^2-26x+169=49 are x=20,x=6

Find the zeros of x^2-26x+169=49

The zeros of x^2-26x+169=49 are x=20,x=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 26 x + 169 = 49

x = 20, x = 6

Solution steps

x^{2} - 26 x + 169 = 49

Move

49

to the left side

x^{2} - 26 x + 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 1 \cdot 120}{2 \cdot 1}

(- 26)^{2} - 4 \cdot 1 \cdot 120 = 14

x_{1, 2} = \frac{- ( - 26 ) \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 14}{2 \cdot 1}, x_{2} = \frac{- ( - 26 ) - 14}{2 \cdot 1}

x = \frac{- ( - 26 ) + 14}{2 \cdot 1} : 20

x = \frac{- ( - 26 ) - 14}{2 \cdot 1} : 6

The solutions to the quadratic equation are:

x = 20, x = 6

3 (x - 5)^{2} = 33

0 = x^{2} + 2

3 (x - 6)^{2} - 45 = 42

3 x^{2} + 4 = 166

4 (x^{2} - 5) - 1 = 3

What are the solutions to the equation x^2-26x+169=49 ?
The solutions to the equation x^2-26x+169=49 are x=20,x=6
Find the zeros of x^2-26x+169=49
The zeros of x^2-26x+169=49 are x=20,x=6