What are the solutions to the equation 5k^2-9k+18=4k^2 ?

The solutions to the equation 5k^2-9k+18=4k^2 are k=6,k=3

Find the zeros of 5k^2-9k+18=4k^2

The zeros of 5k^2-9k+18=4k^2 are k=6,k=3

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5 k^{2} - 9 k + 18 = 4 k^{2}

k = 6, k = 3

Solution steps

5 k^{2} - 9 k + 18 = 4 k^{2}

Move

4 k^{2}

to the left side

k^{2} - 9 k + 18 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 18 = 3

k_{1, 2} = \frac{- ( - 9 ) \pm 3}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 9 ) + 3}{2 \cdot 1}, k_{2} = \frac{- ( - 9 ) - 3}{2 \cdot 1}

k = \frac{- ( - 9 ) + 3}{2 \cdot 1} : 6

k = \frac{- ( - 9 ) - 3}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

k = 6, k = 3

s^{2} + 4 s + 13

3 x^{2} + 66 = - 30 x

s^{2} + 4 s + 5

6 x^{2} + 48 x + 90 = 0

x^{2} - 18 x + 228 = 0

What are the solutions to the equation 5k^2-9k+18=4k^2 ?
The solutions to the equation 5k^2-9k+18=4k^2 are k=6,k=3
Find the zeros of 5k^2-9k+18=4k^2
The zeros of 5k^2-9k+18=4k^2 are k=6,k=3