What are the solutions to the equation solvefor a,y=(a-b/x)^2 ?

The solutions to the equation solvefor a,y=(a-b/x)^2 are a=sqrt(y)+b/x ,a=-sqrt(y)+b/x

Find the zeros of solvefor a,y=(a-b/x)^2

The zeros of solvefor a,y=(a-b/x)^2 are a=sqrt(y)+b/x ,a=-sqrt(y)+b/x

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solve for

a, y = (a - \frac{b}{x})^{2}

a = y + \frac{b}{x}, a = - y + \frac{b}{x}

Solution steps

y = (a - \frac{b}{x})^{2}

Switch sides

(a - \frac{b}{x})^{2} = y

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

a - \frac{b}{x} = y : a = y + \frac{b}{x}

Solve

a - \frac{b}{x} = - y : a = - y + \frac{b}{x}

The solutions to the quadratic equation are:

a = y + \frac{b}{x}, a = - y + \frac{b}{x}

2 (x - 8)^{2} + 20 = 26

X^{2} + 6 X - 16 = 0

3 m^{2} - m - 11 = - 6

y^{2} + 2 y - 3 = 0

x^{2} - 11 x = 24

What are the solutions to the equation solvefor a,y=(a-b/x)^2 ?
The solutions to the equation solvefor a,y=(a-b/x)^2 are a=sqrt(y)+b/x ,a=-sqrt(y)+b/x
Find the zeros of solvefor a,y=(a-b/x)^2
The zeros of solvefor a,y=(a-b/x)^2 are a=sqrt(y)+b/x ,a=-sqrt(y)+b/x