What are the solutions to the equation solvefor b,s(t)=b^2 ?

The solutions to the equation solvefor b,s(t)=b^2 are b=sqrt(st),b=-sqrt(st)

Find the zeros of solvefor b,s(t)=b^2

The zeros of solvefor b,s(t)=b^2 are b=sqrt(st),b=-sqrt(st)

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solve for

b, s (t) = b^{2}

b = s t, b = - s t

Solution steps

s (t) = b^{2}

Switch sides

b^{2} = s t

Remove parentheses:

(a) = a

b^{2} = s t

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = s t, b = - s t

x^{2} - 3 x - 4 = 0

5 x^{2} + 10 x - 9 = 3 x - 3

X^{2} + X - 20 = 0

x^{2} = 19 x - 88

2 x^{2} + 28 x - 30 = 0

What are the solutions to the equation solvefor b,s(t)=b^2 ?
The solutions to the equation solvefor b,s(t)=b^2 are b=sqrt(st),b=-sqrt(st)
Find the zeros of solvefor b,s(t)=b^2
The zeros of solvefor b,s(t)=b^2 are b=sqrt(st),b=-sqrt(st)