What are the solutions to the equation x^2+18x-27=0 ?

The solutions to the equation x^2+18x-27=0 are x=3(2sqrt(3)-3),x=-3(3+2sqrt(3))

Find the zeros of x^2+18x-27=0

The zeros of x^2+18x-27=0 are x=3(2sqrt(3)-3),x=-3(3+2sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 18 x - 27 = 0

x = 3 (23 - 3), x = - 3 (3 + 23)

Decimal Notation

x = 1.39230 \dots, x = - 19.39230 \dots

Solution steps

x^{2} + 18 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot ( - 27 )}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot (- 27) = 123

x_{1, 2} = \frac{- 18 \pm 12 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 12 3}{2 \cdot 1}, x_{2} = \frac{- 18 - 12 3}{2 \cdot 1}

x = \frac{- 18 + 12 3}{2 \cdot 1} : 3 (23 - 3)

x = \frac{- 18 - 12 3}{2 \cdot 1} : - 3 (3 + 23)

The solutions to the quadratic equation are:

x = 3 (23 - 3), x = - 3 (3 + 23)

2 x^{2} - 36 = 0

x, f = 2 x^{2} - 3 y - 4

8 x^{2} + 2 x - 1 = 0

x, 2 x^{2} + y^{2} - 4 x + 2 y + 3 = 0

3 x^{2} + 11 x = 4

What are the solutions to the equation x^2+18x-27=0 ?
The solutions to the equation x^2+18x-27=0 are x=3(2sqrt(3)-3),x=-3(3+2sqrt(3))
Find the zeros of x^2+18x-27=0
The zeros of x^2+18x-27=0 are x=3(2sqrt(3)-3),x=-3(3+2sqrt(3))