What are the solutions to the equation 3(x-7)^2+34=46 ?

The solutions to the equation 3(x-7)^2+34=46 are x=9,x=5

Find the zeros of 3(x-7)^2+34=46

The zeros of 3(x-7)^2+34=46 are x=9,x=5

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3 (x - 7)^{2} + 34 = 46

x = 9, x = 5

Solution steps

3 (x - 7)^{2} + 34 = 46

Move

34

to the right side

3 (x - 7)^{2} = 12

Divide both sides by

3

(x - 7)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 7 = 4 : x = 9

Solve

x - 7 = - 4 : x = 5

The solutions to the quadratic equation are:

x = 9, x = 5

x^{2} + x - 6 = 0

3 x^{2} - 14 x - 4 = - 10 x

x, z = x^{2} - x y^{2} + 4 y^{5}

2 x^{2} - 20 x + 48 = 0

x^{2} - 8 x + 16 = 289

What are the solutions to the equation 3(x-7)^2+34=46 ?
The solutions to the equation 3(x-7)^2+34=46 are x=9,x=5
Find the zeros of 3(x-7)^2+34=46
The zeros of 3(x-7)^2+34=46 are x=9,x=5