What is -2x^3+x^2+13x+6<0 ?

The solution to -2x^3+x^2+13x+6 3

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-2x^3+x^2+13x+6<0

- 2 x^{3} + x^{2} + 13 x + 6 < 0

- 2 < x < - \frac{1}{2} or x > 3

Solution steps

- 2 x^{3} + x^{2} + 13 x + 6 < 0

Factor

- 2 x^{3} + x^{2} + 13 x + 6 : - (x + 2) (2 x + 1) (x - 3)

- (x + 2) (2 x + 1) (x - 3) < 0

Multiply both sides by

- 1

(reverse the inequality)

(- (x + 2) (2 x + 1) (x - 3)) (- 1) > 0 \cdot (- 1)

Simplify

(x + 2) (2 x + 1) (x - 3) > 0

Identify the intervals

- 2 < x < - \frac{1}{2} or x > 3

2 n - 36 < \frac{1}{3} n + 15

- \frac{23}{2} (\frac{1}{10 0 ^{2}}) + \frac{23}{2}

(3 x^{\frac{1}{3}})^{2}

40 \cdot 0.4

7 - 14 m = 2 m - 5

What is -2x^3+x^2+13x+6<0 ?
The solution to -2x^3+x^2+13x+6<0 is -2<x<-1/2 \lor x>3