What are the solutions to the equation -5p^2+8p-8=-6p^2 ?

The solutions to the equation -5p^2+8p-8=-6p^2 are p=2(sqrt(6)-2),p=-2(2+sqrt(6))

Find the zeros of -5p^2+8p-8=-6p^2

The zeros of -5p^2+8p-8=-6p^2 are p=2(sqrt(6)-2),p=-2(2+sqrt(6))

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- 5 p^{2} + 8 p - 8 = - 6 p^{2}

p = 2 (6 - 2), p = - 2 (2 + 6)

Decimal Notation

p = 0.89897 \dots, p = - 8.89897 \dots

Solution steps

- 5 p^{2} + 8 p - 8 = - 6 p^{2}

Move

6 p^{2}

to the left side

p^{2} + 8 p - 8 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 8) = 46

p_{1, 2} = \frac{- 8 \pm 4 6}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 8 + 4 6}{2 \cdot 1}, p_{2} = \frac{- 8 - 4 6}{2 \cdot 1}

p = \frac{- 8 + 4 6}{2 \cdot 1} : 2 (6 - 2)

p = \frac{- 8 - 4 6}{2 \cdot 1} : - 2 (2 + 6)

The solutions to the quadratic equation are:

p = 2 (6 - 2), p = - 2 (2 + 6)

12 x^{2} - 24 x + 8 = 0

y^{2} + 9 y + 18 = 0

x, 9 x^{2} + 4 x y + 6 y^{2} + 12 x + 36 y + 44 = 0

0 = x^{2} - 6 x + 10

x^{2} + 6 x + 9

What are the solutions to the equation -5p^2+8p-8=-6p^2 ?
The solutions to the equation -5p^2+8p-8=-6p^2 are p=2(sqrt(6)-2),p=-2(2+sqrt(6))
Find the zeros of -5p^2+8p-8=-6p^2
The zeros of -5p^2+8p-8=-6p^2 are p=2(sqrt(6)-2),p=-2(2+sqrt(6))