What are the solutions to the equation (2x-6)^2=8 ?

The solutions to the equation (2x-6)^2=8 are x=sqrt(2)+3,x=-sqrt(2)+3

Find the zeros of (2x-6)^2=8

The zeros of (2x-6)^2=8 are x=sqrt(2)+3,x=-sqrt(2)+3

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(2 x - 6)^{2} = 8

x = 2 + 3, x = - 2 + 3

Decimal Notation

x = 4.41421 \dots, x = 1.58578 \dots

Solution steps

(2 x - 6)^{2} = 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 6 = 8 : x = 2 + 3

Solve

2 x - 6 = - 8 : x = - 2 + 3

The solutions to the quadratic equation are:

x = 2 + 3, x = - 2 + 3

2 = x^{2}

2 m^{2} + 3 m - 2 = 0

3 x^{2} + 15 x + 19 = 0

k^{2} = - 49

x^{2} + 16 x + 19 = 0

What are the solutions to the equation (2x-6)^2=8 ?
The solutions to the equation (2x-6)^2=8 are x=sqrt(2)+3,x=-sqrt(2)+3
Find the zeros of (2x-6)^2=8
The zeros of (2x-6)^2=8 are x=sqrt(2)+3,x=-sqrt(2)+3