What are the solutions to the equation 5x^2-6x-3=0 ?

The solutions to the equation 5x^2-6x-3=0 are x=(3+2sqrt(6))/5 ,x=(3-2sqrt(6))/5

Find the zeros of 5x^2-6x-3=0

The zeros of 5x^2-6x-3=0 are x=(3+2sqrt(6))/5 ,x=(3-2sqrt(6))/5

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5 x^{2} - 6 x - 3 = 0

x = \frac{3 + 2 6}{5}, x = \frac{3 - 2 6}{5}

Decimal Notation

x = 1.57979 \dots, x = - 0.37979 \dots

Solution steps

5 x^{2} - 6 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 5 ( - 3 )}{2 \cdot 5}

(- 6)^{2} - 4 \cdot 5 (- 3) = 46

x_{1, 2} = \frac{- ( - 6 ) \pm 4 6}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 4 6}{2 \cdot 5}, x_{2} = \frac{- ( - 6 ) - 4 6}{2 \cdot 5}

x = \frac{- ( - 6 ) + 4 6}{2 \cdot 5} : \frac{3 + 2 6}{5}

x = \frac{- ( - 6 ) - 4 6}{2 \cdot 5} : \frac{3 - 2 6}{5}

The solutions to the quadratic equation are:

x = \frac{3 + 2 6}{5}, x = \frac{3 - 2 6}{5}

2 n^{2} + 4 n = 0

x^{2} - 10 x + 3 = 0

(x + 23)^{2} = - 10

2 x^{2} - 22 = 16 x

x^{2} + 51 = - 15 x + 1

What are the solutions to the equation 5x^2-6x-3=0 ?
The solutions to the equation 5x^2-6x-3=0 are x=(3+2sqrt(6))/5 ,x=(3-2sqrt(6))/5
Find the zeros of 5x^2-6x-3=0
The zeros of 5x^2-6x-3=0 are x=(3+2sqrt(6))/5 ,x=(3-2sqrt(6))/5