What are the solutions to the equation 3x^2-6x+12=0 ?

The solutions to the equation 3x^2-6x+12=0 are x=1+sqrt(3)i,x=1-sqrt(3)i

Find the zeros of 3x^2-6x+12=0

The zeros of 3x^2-6x+12=0 are x=1+sqrt(3)i,x=1-sqrt(3)i

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3 x^{2} - 6 x + 12 = 0

x = 1 + 3 i, x = 1 - 3 i

Solution steps

3 x^{2} - 6 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

Simplify

(- 6)^{2} - 4 \cdot 3 \cdot 12 : 63 i

x_{1, 2} = \frac{- ( - 6 ) \pm 6 3 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 3 i}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 6 3 i}{2 \cdot 3}

x = \frac{- ( - 6 ) + 6 3 i}{2 \cdot 3} : 1 + 3 i

x = \frac{- ( - 6 ) - 6 3 i}{2 \cdot 3} : 1 - 3 i

The solutions to the quadratic equation are:

x = 1 + 3 i, x = 1 - 3 i

2 x^{2} = 200

1 + 3 + 5 + (2 n - 1) = n^{2}

x^{2} + x - 48 = 3 x

7 x^{2} + 28 x = 0

x, x^{2} + y^{2} + 6 x + 2 y + 10 = 0

What are the solutions to the equation 3x^2-6x+12=0 ?
The solutions to the equation 3x^2-6x+12=0 are x=1+sqrt(3)i,x=1-sqrt(3)i
Find the zeros of 3x^2-6x+12=0
The zeros of 3x^2-6x+12=0 are x=1+sqrt(3)i,x=1-sqrt(3)i