What are the solutions to the equation x^2+8x=-20 ?

The solutions to the equation x^2+8x=-20 are x=-4+2i,x=-4-2i

Find the zeros of x^2+8x=-20

The zeros of x^2+8x=-20 are x=-4+2i,x=-4-2i

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x^{2} + 8 x = - 20

x = - 4 + 2 i, x = - 4 - 2 i

Solution steps

x^{2} + 8 x = - 20

Move

20

to the left side

x^{2} + 8 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 20 : 4 i

x_{1, 2} = \frac{- 8 \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 4 i}{2 \cdot 1}, x_{2} = \frac{- 8 - 4 i}{2 \cdot 1}

x = \frac{- 8 + 4 i}{2 \cdot 1} : - 4 + 2 i

x = \frac{- 8 - 4 i}{2 \cdot 1} : - 4 - 2 i

The solutions to the quadratic equation are:

x = - 4 + 2 i, x = - 4 - 2 i

x^{2} - 4 x - 12 = 0

5 x^{2} - 39 x - 4 = 4

8 x^{2} - 32 = 0

x, x^{2} = y (x + 6 y)

5 x = 2 x^{2} + 15

What are the solutions to the equation x^2+8x=-20 ?
The solutions to the equation x^2+8x=-20 are x=-4+2i,x=-4-2i
Find the zeros of x^2+8x=-20
The zeros of x^2+8x=-20 are x=-4+2i,x=-4-2i