What are the solutions to the equation -x^2+2x=1 ?

The solutions to the equation -x^2+2x=1 are x=1

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-x^2+2x=1

- x^{2} + 2 x = 1

x = 1

Solution steps

- x^{2} + 2 x = 1

Move

1

to the left side

- x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) ( - 1 )}{2 ( - 1 )}

2^{2} - 4 (- 1) (- 1) = 0

x_{1, 2} = \frac{- 2 \pm 0}{2 ( - 1 )}

x = \frac{- 2}{2 ( - 1 )}

\frac{- 2}{2 ( - 1 )} = 1

x = 1

The solution to the quadratic equation is:

x = 1

18 - 2 x^{2} = - 28

x, x^{2} - 4 x + 3 = 0

- 2 x^{2} + 6 x - 7 = 0

x^{2} - 6 x + 8

x^{2} - 6 x + 4 = - 7 x + 6

What are the solutions to the equation -x^2+2x=1 ?
The solutions to the equation -x^2+2x=1 are x=1
Find the zeros of -x^2+2x=1
The zeros of -x^2+2x=1 are x=1