What are the solutions to the equation 3x^2+4x+5=0 ?

The solutions to the equation 3x^2+4x+5=0 are x=-2/3+i(sqrt(11))/3 ,x=-2/3-i(sqrt(11))/3

Find the zeros of 3x^2+4x+5=0

The zeros of 3x^2+4x+5=0 are x=-2/3+i(sqrt(11))/3 ,x=-2/3-i(sqrt(11))/3

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3 x^{2} + 4 x + 5 = 0

x = - \frac{2}{3} + i \frac{11}{3}, x = - \frac{2}{3} - i \frac{11}{3}

Solution steps

3 x^{2} + 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

Simplify

4^{2} - 4 \cdot 3 \cdot 5 : 211 i

x_{1, 2} = \frac{- 4 \pm 2 11 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 2 11 i}{2 \cdot 3}, x_{2} = \frac{- 4 - 2 11 i}{2 \cdot 3}

x = \frac{- 4 + 2 11 i}{2 \cdot 3} : - \frac{2}{3} + i \frac{11}{3}

x = \frac{- 4 - 2 11 i}{2 \cdot 3} : - \frac{2}{3} - i \frac{11}{3}

The solutions to the quadratic equation are:

x = - \frac{2}{3} + i \frac{11}{3}, x = - \frac{2}{3} - i \frac{11}{3}

(- 32)^{\frac{6}{3}}

10 - 3 r < 1

625 - x^{4}

71 + (- 5 x + (- 2 x + 3)) = 25 - (- (3 x + 4) - (4 x + 3))

(x + 2) (x - 3) (x + 6) \leq 0

What are the solutions to the equation 3x^2+4x+5=0 ?
The solutions to the equation 3x^2+4x+5=0 are x=-2/3+i(sqrt(11))/3 ,x=-2/3-i(sqrt(11))/3
Find the zeros of 3x^2+4x+5=0
The zeros of 3x^2+4x+5=0 are x=-2/3+i(sqrt(11))/3 ,x=-2/3-i(sqrt(11))/3