What are the solutions to the equation 10+5b^2=200 ?

The solutions to the equation 10+5b^2=200 are b=sqrt(38),b=-sqrt(38)

Find the zeros of 10+5b^2=200

The zeros of 10+5b^2=200 are b=sqrt(38),b=-sqrt(38)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

10 + 5 b^{2} = 200

b = 38, b = - 38

Decimal Notation

b = 6.16441 \dots, b = - 6.16441 \dots

Solution steps

10 + 5 b^{2} = 200

Move

10

to the right side

5 b^{2} = 190

Divide both sides by

5

b^{2} = 38

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 38, b = - 38

- 12 x^{2} + 4 = 0

x^{2} + 23 x + 120 = 0

x, 2 x^{2} + y^{2} + 4 x - 8 y + 18 = 0

\frac{3}{4} x^{2} = \frac{5}{4} x + \frac{1}{2}

x^{2} - 4 x + 3 = - x^{2} + 2 x + 3

What are the solutions to the equation 10+5b^2=200 ?
The solutions to the equation 10+5b^2=200 are b=sqrt(38),b=-sqrt(38)
Find the zeros of 10+5b^2=200
The zeros of 10+5b^2=200 are b=sqrt(38),b=-sqrt(38)