What are the solutions to the equation 2(x+10)^2-37=13 ?

The solutions to the equation 2(x+10)^2-37=13 are x=-5,x=-15

Find the zeros of 2(x+10)^2-37=13

The zeros of 2(x+10)^2-37=13 are x=-5,x=-15

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2 (x + 10)^{2} - 37 = 13

x = - 5, x = - 15

Solution steps

2 (x + 10)^{2} - 37 = 13

Move

37

to the right side

2 (x + 10)^{2} = 50

Divide both sides by

2

(x + 10)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 10 = 25 : x = - 5

Solve

x + 10 = - 25 : x = - 15

The solutions to the quadratic equation are:

x = - 5, x = - 15

x^{2} - 72 = 0

x^{2} + x + 2

u, v^{2} = u^{2} + 2 a s

x^{2} - 16 = 0

5 x^{2} + 100 x + 460 = 0

What are the solutions to the equation 2(x+10)^2-37=13 ?
The solutions to the equation 2(x+10)^2-37=13 are x=-5,x=-15
Find the zeros of 2(x+10)^2-37=13
The zeros of 2(x+10)^2-37=13 are x=-5,x=-15