What are the solutions to the equation x^2-8x-63=-10x ?

The solutions to the equation x^2-8x-63=-10x are x=7,x=-9

Find the zeros of x^2-8x-63=-10x

The zeros of x^2-8x-63=-10x are x=7,x=-9

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x^{2} - 8 x - 63 = - 10 x

x = 7, x = - 9

Solution steps

x^{2} - 8 x - 63 = - 10 x

Move

10 x

to the left side

x^{2} + 2 x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 63 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 63) = 16

x_{1, 2} = \frac{- 2 \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 16}{2 \cdot 1}, x_{2} = \frac{- 2 - 16}{2 \cdot 1}

x = \frac{- 2 + 16}{2 \cdot 1} : 7

x = \frac{- 2 - 16}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 7, x = - 9

(x + 2)^{2} + (x + 3)^{2} = (x + 4)^{2}

x, y^{3} + y^{2} - 5 y - x^{2} = - 4

x, 4 x^{2} + 3 y^{2} - 24 y + 144 = 0

x^{2} + 5 x = 7

x^{2} + 5 x = 4

What are the solutions to the equation x^2-8x-63=-10x ?
The solutions to the equation x^2-8x-63=-10x are x=7,x=-9
Find the zeros of x^2-8x-63=-10x
The zeros of x^2-8x-63=-10x are x=7,x=-9