What are the solutions to the equation 6x^2-24x+18=0 ?

The solutions to the equation 6x^2-24x+18=0 are x=3,x=1

Find the zeros of 6x^2-24x+18=0

The zeros of 6x^2-24x+18=0 are x=3,x=1

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6 x^{2} - 24 x + 18 = 0

x = 3, x = 1

Solution steps

6 x^{2} - 24 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 6 \cdot 18}{2 \cdot 6}

(- 24)^{2} - 4 \cdot 6 \cdot 18 = 12

x_{1, 2} = \frac{- ( - 24 ) \pm 12}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 12}{2 \cdot 6}, x_{2} = \frac{- ( - 24 ) - 12}{2 \cdot 6}

x = \frac{- ( - 24 ) + 12}{2 \cdot 6} : 3

x = \frac{- ( - 24 ) - 12}{2 \cdot 6} : 1

The solutions to the quadratic equation are:

x = 3, x = 1

2 x^{2} + 8 x - 3

3 + x = x^{2} + 3 x

x^{2} - x - 6 = 0

x^{2} + 2 x + 12 = 0

y^{2} - 10 y + 25 = 0

What are the solutions to the equation 6x^2-24x+18=0 ?
The solutions to the equation 6x^2-24x+18=0 are x=3,x=1
Find the zeros of 6x^2-24x+18=0
The zeros of 6x^2-24x+18=0 are x=3,x=1