What are the solutions to the equation m^2-6m-17=-5 ?

The solutions to the equation m^2-6m-17=-5 are m=3+sqrt(21),m=3-sqrt(21)

Find the zeros of m^2-6m-17=-5

The zeros of m^2-6m-17=-5 are m=3+sqrt(21),m=3-sqrt(21)

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m^{2} - 6 m - 17 = - 5

m = 3 + 21, m = 3 - 21

Decimal Notation

m = 7.58257 \dots, m = - 1.58257 \dots

Solution steps

m^{2} - 6 m - 17 = - 5

Move

5

to the left side

m^{2} - 6 m - 12 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 12) = 221

m_{1, 2} = \frac{- ( - 6 ) \pm 2 21}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 6 ) + 2 21}{2 \cdot 1}, m_{2} = \frac{- ( - 6 ) - 2 21}{2 \cdot 1}

m = \frac{- ( - 6 ) + 2 21}{2 \cdot 1} : 3 + 21

m = \frac{- ( - 6 ) - 2 21}{2 \cdot 1} : 3 - 21

The solutions to the quadratic equation are:

m = 3 + 21, m = 3 - 21

1.15 (0.85 - 2 x)^{2} = x

5 n^{2} - 2 = - 92

3 (x - 3)^{2} + 2 = 26

4 x^{2} = 5 x - 10

4 (x - 7)^{2} - 2 = 2

What are the solutions to the equation m^2-6m-17=-5 ?
The solutions to the equation m^2-6m-17=-5 are m=3+sqrt(21),m=3-sqrt(21)
Find the zeros of m^2-6m-17=-5
The zeros of m^2-6m-17=-5 are m=3+sqrt(21),m=3-sqrt(21)