What are the solutions to the equation x^2-16x+68=0 ?

The solutions to the equation x^2-16x+68=0 are x=8+2i,x=8-2i

Find the zeros of x^2-16x+68=0

The zeros of x^2-16x+68=0 are x=8+2i,x=8-2i

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x^{2} - 16 x + 68 = 0

x = 8 + 2 i, x = 8 - 2 i

Solution steps

x^{2} - 16 x + 68 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 68}{2 \cdot 1}

Simplify

(- 16)^{2} - 4 \cdot 1 \cdot 68 : 4 i

x_{1, 2} = \frac{- ( - 16 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 i}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 4 i}{2 \cdot 1}

x = \frac{- ( - 16 ) + 4 i}{2 \cdot 1} : 8 + 2 i

x = \frac{- ( - 16 ) - 4 i}{2 \cdot 1} : 8 - 2 i

The solutions to the quadratic equation are:

x = 8 + 2 i, x = 8 - 2 i

0.03 x^{2} - 0.9 x + 2.43 = 0

p^{2} - 5 p + 17 = 4 p

4 x^{2} - x - 2 = 0

x^{2} - 8 x + 11 = 0

x^{2} = - 4 x + 32

What are the solutions to the equation x^2-16x+68=0 ?
The solutions to the equation x^2-16x+68=0 are x=8+2i,x=8-2i
Find the zeros of x^2-16x+68=0
The zeros of x^2-16x+68=0 are x=8+2i,x=8-2i