What are the solutions to the equation x(2x+5)=3 ?

The solutions to the equation x(2x+5)=3 are x= 1/2 ,x=-3

Find the zeros of x(2x+5)=3

The zeros of x(2x+5)=3 are x= 1/2 ,x=-3

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x (2 x + 5) = 3

x = \frac{1}{2}, x = - 3

Decimal Notation

x = 0.5, x = - 3

Solution steps

x (2 x + 5) = 3

Expand

x (2 x + 5) : 2 x^{2} + 5 x

2 x^{2} + 5 x = 3

Move

3

to the left side

2 x^{2} + 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 3) = 7

x_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 7}{2 \cdot 2}, x_{2} = \frac{- 5 - 7}{2 \cdot 2}

x = \frac{- 5 + 7}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 5 - 7}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 3

2 x^{2} + 90 = 0

- 2 (x - 2)^{2} + 3 = 0

0.5 x^{2} + 11 x + 3.5 = 0

- x^{2} - 7 x - 12 = 0

- 2 x = x^{2} - 6

What are the solutions to the equation x(2x+5)=3 ?
The solutions to the equation x(2x+5)=3 are x= 1/2 ,x=-3
Find the zeros of x(2x+5)=3
The zeros of x(2x+5)=3 are x= 1/2 ,x=-3