What are the solutions to the equation (x+4)^2-49=0 ?

The solutions to the equation (x+4)^2-49=0 are x=3,x=-11

Find the zeros of (x+4)^2-49=0

The zeros of (x+4)^2-49=0 are x=3,x=-11

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 4)^{2} - 49 = 0

x = 3, x = - 11

Solution steps

(x + 4)^{2} - 49 = 0

Move

49

to the right side

(x + 4)^{2} = 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 49 : x = 3

Solve

x + 4 = - 49 : x = - 11

The solutions to the quadratic equation are:

x = 3, x = - 11

3 x + 6 = - 6 x^{2}

x^{2} + 4 x = 4

24 x^{2} = 0

x, x^{2} + x y + y^{2} = 4

- x^{2} + 2 x + 12 = 0

What are the solutions to the equation (x+4)^2-49=0 ?
The solutions to the equation (x+4)^2-49=0 are x=3,x=-11
Find the zeros of (x+4)^2-49=0
The zeros of (x+4)^2-49=0 are x=3,x=-11