What are the solutions to the equation 0=-16t^2+112t ?

The solutions to the equation 0=-16t^2+112t are t=0,t=7

Find the zeros of 0=-16t^2+112t

The zeros of 0=-16t^2+112t are t=0,t=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = - 16 t^{2} + 112 t

t = 0, t = 7

Solution steps

0 = - 16 t^{2} + 112 t

Switch sides

- 16 t^{2} + 112 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 112 \pm 11 2 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

11 2^{2} - 4 (- 16) \cdot 0 = 112

t_{1, 2} = \frac{- 112 \pm 112}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 112 + 112}{2 ( - 16 )}, t_{2} = \frac{- 112 - 112}{2 ( - 16 )}

t = \frac{- 112 + 112}{2 ( - 16 )} : 0

t = \frac{- 112 - 112}{2 ( - 16 )} : 7

The solutions to the quadratic equation are:

t = 0, t = 7

2 x^{2} - 19 x + 9 = 0

0 = 128 t - 16 t^{2}

\frac{4 x + 7}{12} + x = \frac{3 x}{8}

\frac{8}{2 + 6 i}

6 4^{- \frac{4}{3}}

What are the solutions to the equation 0=-16t^2+112t ?
The solutions to the equation 0=-16t^2+112t are t=0,t=7
Find the zeros of 0=-16t^2+112t
The zeros of 0=-16t^2+112t are t=0,t=7