What are the solutions to the equation 176x=121+64x^2 ?

The solutions to the equation 176x=121+64x^2 are x= 11/8

Find the zeros of 176x=121+64x^2

The zeros of 176x=121+64x^2 are x= 11/8

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176 x = 121 + 64 x^{2}

x = \frac{11}{8}

Decimal

x = 1.375

Solution steps

176 x = 121 + 64 x^{2}

Switch sides

121 + 64 x^{2} = 176 x

Move

176 x

to the left side

121 + 64 x^{2} - 176 x = 0

Write in the standard form

a x^{2} + b x + c = 0

64 x^{2} - 176 x + 121 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 176 ) \pm ( - 176 ) ^{2} - 4 \cdot 64 \cdot 121}{2 \cdot 64}

(- 176)^{2} - 4 \cdot 64 \cdot 121 = 0

x_{1, 2} = \frac{- ( - 176 ) \pm 0}{2 \cdot 64}

x = \frac{- ( - 176 )}{2 \cdot 64}

\frac{- ( - 176 )}{2 \cdot 64} = \frac{11}{8}

x = \frac{11}{8}

The solution to the quadratic equation is:

x = \frac{11}{8}

3 x^{2} - 300 = 0

(x + 8)^{2} - 43 = - 38

z^{2} - 17 z + 12 = - 5 z

3 x^{2} = - x + 4

x, y = 4 - x^{2}

What are the solutions to the equation 176x=121+64x^2 ?
The solutions to the equation 176x=121+64x^2 are x= 11/8
Find the zeros of 176x=121+64x^2
The zeros of 176x=121+64x^2 are x= 11/8