What are the solutions to the equation -6x^2-96x-90=0 ?

The solutions to the equation -6x^2-96x-90=0 are x=-15,x=-1

Find the zeros of -6x^2-96x-90=0

The zeros of -6x^2-96x-90=0 are x=-15,x=-1

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- 6 x^{2} - 96 x - 90 = 0

x = - 15, x = - 1

Solution steps

- 6 x^{2} - 96 x - 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 96 ) \pm ( - 96 ) ^{2} - 4 ( - 6 ) ( - 90 )}{2 ( - 6 )}

(- 96)^{2} - 4 (- 6) (- 90) = 84

x_{1, 2} = \frac{- ( - 96 ) \pm 84}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 96 ) + 84}{2 ( - 6 )}, x_{2} = \frac{- ( - 96 ) - 84}{2 ( - 6 )}

x = \frac{- ( - 96 ) + 84}{2 ( - 6 )} : - 15

x = \frac{- ( - 96 ) - 84}{2 ( - 6 )} : - 1

The solutions to the quadratic equation are:

x = - 15, x = - 1

2 4^{2} + 1 0^{2} = x^{2}

(x - 3) (x + 6) = 0

5 (5 x - 8)^{2} = 5

4 x^{2} - 14 x - 5

x, x^{2} + 5 y^{2} = - 8

What are the solutions to the equation -6x^2-96x-90=0 ?
The solutions to the equation -6x^2-96x-90=0 are x=-15,x=-1
Find the zeros of -6x^2-96x-90=0
The zeros of -6x^2-96x-90=0 are x=-15,x=-1