What are the solutions to the equation solvefor x,x^2+y^2-2y+4=0 ?

The solutions to the equation solvefor x,x^2+y^2-2y+4=0 are x=sqrt(-y^2+2y-4),x=-sqrt(-y^2+2y-4)

Find the zeros of solvefor x,x^2+y^2-2y+4=0

The zeros of solvefor x,x^2+y^2-2y+4=0 are x=sqrt(-y^2+2y-4),x=-sqrt(-y^2+2y-4)

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solve for

x, x^{2} + y^{2} - 2 y + 4 = 0

x = - y^{2} + 2 y - 4, x = - - y^{2} + 2 y - 4

Solution steps

x^{2} + y^{2} - 2 y + 4 = 0

Move

y^{2}

to the right side

x^{2} - 2 y + 4 = - y^{2}

Move

2 y

to the right side

x^{2} + 4 = - y^{2} + 2 y

Move

4

to the right side

x^{2} = - y^{2} + 2 y - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - y^{2} + 2 y - 4, x = - - y^{2} + 2 y - 4

f, h = f (x + f)

(x + 5) (x - 2) = 0

x, 2 x^{2} - 4 x y - y^{2} - 4 x - 8 y + 62 = 0

18 z^{2} - 31 z + 12 = - 2 z^{2}

4 x^{2} - 30 = 22

What are the solutions to the equation solvefor x,x^2+y^2-2y+4=0 ?
The solutions to the equation solvefor x,x^2+y^2-2y+4=0 are x=sqrt(-y^2+2y-4),x=-sqrt(-y^2+2y-4)
Find the zeros of solvefor x,x^2+y^2-2y+4=0
The zeros of solvefor x,x^2+y^2-2y+4=0 are x=sqrt(-y^2+2y-4),x=-sqrt(-y^2+2y-4)