What are the solutions to the equation 2(x+10)^2-34=-26 ?

The solutions to the equation 2(x+10)^2-34=-26 are x=-8,x=-12

Find the zeros of 2(x+10)^2-34=-26

The zeros of 2(x+10)^2-34=-26 are x=-8,x=-12

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2 (x + 10)^{2} - 34 = - 26

x = - 8, x = - 12

Solution steps

2 (x + 10)^{2} - 34 = - 26

Move

34

to the right side

2 (x + 10)^{2} = 8

Divide both sides by

2

(x + 10)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 10 = 4 : x = - 8

Solve

x + 10 = - 4 : x = - 12

The solutions to the quadratic equation are:

x = - 8, x = - 12

7 r^{2} - 5 = 2 r + 9 r^{2}

(\frac{1}{h ^{- 2}})^{- 1} \cdot h^{3}

\frac{3}{2} + 8

\frac{3}{8} r - 6 < 15

1 0^{2} + 1 5^{2} = x^{2}

What are the solutions to the equation 2(x+10)^2-34=-26 ?
The solutions to the equation 2(x+10)^2-34=-26 are x=-8,x=-12
Find the zeros of 2(x+10)^2-34=-26
The zeros of 2(x+10)^2-34=-26 are x=-8,x=-12