What are the solutions to the equation -2x^2-28x-102=0 ?

The solutions to the equation -2x^2-28x-102=0 are x=-7-sqrt(2)i,x=-7+sqrt(2)i

Find the zeros of -2x^2-28x-102=0

The zeros of -2x^2-28x-102=0 are x=-7-sqrt(2)i,x=-7+sqrt(2)i

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- 2 x^{2} - 28 x - 102 = 0

x = - 7 - 2 i, x = - 7 + 2 i

Solution steps

- 2 x^{2} - 28 x - 102 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 ( - 2 ) ( - 102 )}{2 ( - 2 )}

Simplify

(- 28)^{2} - 4 (- 2) (- 102) : 42 i

x_{1, 2} = \frac{- ( - 28 ) \pm 4 2 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 28 ) + 4 2 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 28 ) - 4 2 i}{2 ( - 2 )}

x = \frac{- ( - 28 ) + 4 2 i}{2 ( - 2 )} : - 7 - 2 i

x = \frac{- ( - 28 ) - 4 2 i}{2 ( - 2 )} : - 7 + 2 i

The solutions to the quadratic equation are:

x = - 7 - 2 i, x = - 7 + 2 i

3 x^{2} + 3 = 7 x - 1

4 (x + 1)^{2} + 28 = 40

x^{2} - 4 x + 15 = 0

2 (x + 8)^{2} + 9 = 29

x^{2} + 6 x + 8 = 0

What are the solutions to the equation -2x^2-28x-102=0 ?
The solutions to the equation -2x^2-28x-102=0 are x=-7-sqrt(2)i,x=-7+sqrt(2)i
Find the zeros of -2x^2-28x-102=0
The zeros of -2x^2-28x-102=0 are x=-7-sqrt(2)i,x=-7+sqrt(2)i