What are the solutions to the equation -5x^2+40x-100=0 ?

The solutions to the equation -5x^2+40x-100=0 are x=4-2i,x=4+2i

Find the zeros of -5x^2+40x-100=0

The zeros of -5x^2+40x-100=0 are x=4-2i,x=4+2i

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- 5 x^{2} + 40 x - 100 = 0

x = 4 - 2 i, x = 4 + 2 i

Solution steps

- 5 x^{2} + 40 x - 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 ( - 5 ) ( - 100 )}{2 ( - 5 )}

Simplify

4 0^{2} - 4 (- 5) (- 100) : 20 i

x_{1, 2} = \frac{- 40 \pm 20 i}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 40 + 20 i}{2 ( - 5 )}, x_{2} = \frac{- 40 - 20 i}{2 ( - 5 )}

x = \frac{- 40 + 20 i}{2 ( - 5 )} : 4 - 2 i

x = \frac{- 40 - 20 i}{2 ( - 5 )} : 4 + 2 i

The solutions to the quadratic equation are:

x = 4 - 2 i, x = 4 + 2 i

2 n^{2} - 18 n + 40 = 0

729 = 9 x^{2}

x^{2} - 94 = - x - 4

6 y^{2} - 13 y + 12 = 4 y^{2}

2 x^{2} - 13 = - 5 x - 10

What are the solutions to the equation -5x^2+40x-100=0 ?
The solutions to the equation -5x^2+40x-100=0 are x=4-2i,x=4+2i
Find the zeros of -5x^2+40x-100=0
The zeros of -5x^2+40x-100=0 are x=4-2i,x=4+2i