What are the solutions to the equation 24=x^2-4x+3 ?

The solutions to the equation 24=x^2-4x+3 are x=7,x=-3

Find the zeros of 24=x^2-4x+3

The zeros of 24=x^2-4x+3 are x=7,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

24 = x^{2} - 4 x + 3

x = 7, x = - 3

Solution steps

24 = x^{2} - 4 x + 3

Switch sides

x^{2} - 4 x + 3 = 24

Move

24

to the left side

x^{2} - 4 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 21 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 21) = 10

x_{1, 2} = \frac{- ( - 4 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 10}{2 \cdot 1}

x = \frac{- ( - 4 ) + 10}{2 \cdot 1} : 7

x = \frac{- ( - 4 ) - 10}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 7, x = - 3

x, x^{2} y^{2} - x y + x = 1

r, v = \frac{1}{3} (π r^{2}) h

2 x^{2} + 16 x + 14 = 0

5 (x + 10)^{2} - 30 = - 5

8 x^{2} - 3 = 597

What are the solutions to the equation 24=x^2-4x+3 ?
The solutions to the equation 24=x^2-4x+3 are x=7,x=-3
Find the zeros of 24=x^2-4x+3
The zeros of 24=x^2-4x+3 are x=7,x=-3