What are the solutions to the equation 4x^2+36x=-73 ?

The solutions to the equation 4x^2+36x=-73 are x=(-9+2sqrt(2))/2 ,x=-(9+2sqrt(2))/2

Find the zeros of 4x^2+36x=-73

The zeros of 4x^2+36x=-73 are x=(-9+2sqrt(2))/2 ,x=-(9+2sqrt(2))/2

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4 x^{2} + 36 x = - 73

x = \frac{- 9 + 2 2}{2}, x = - \frac{9 + 2 2}{2}

Decimal Notation

x = - 3.08578 \dots, x = - 5.91421 \dots

Solution steps

4 x^{2} + 36 x = - 73

Move

73

to the left side

4 x^{2} + 36 x + 73 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 4 \cdot 73}{2 \cdot 4}

3 6^{2} - 4 \cdot 4 \cdot 73 = 82

x_{1, 2} = \frac{- 36 \pm 8 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 36 + 8 2}{2 \cdot 4}, x_{2} = \frac{- 36 - 8 2}{2 \cdot 4}

x = \frac{- 36 + 8 2}{2 \cdot 4} : \frac{- 9 + 2 2}{2}

x = \frac{- 36 - 8 2}{2 \cdot 4} : - \frac{9 + 2 2}{2}

The solutions to the quadratic equation are:

x = \frac{- 9 + 2 2}{2}, x = - \frac{9 + 2 2}{2}

x^{2} - 16 x + 15 = 0

x^{2} - 4 x = - x^{2}

(x + 3) (x + 14) = 0

5 x^{2} = 10 x

1 0^{2} = 6^{2} + x^{2}

What are the solutions to the equation 4x^2+36x=-73 ?
The solutions to the equation 4x^2+36x=-73 are x=(-9+2sqrt(2))/2 ,x=-(9+2sqrt(2))/2
Find the zeros of 4x^2+36x=-73
The zeros of 4x^2+36x=-73 are x=(-9+2sqrt(2))/2 ,x=-(9+2sqrt(2))/2