What are the solutions to the equation x^2-20x+100=25 ?

The solutions to the equation x^2-20x+100=25 are x=15,x=5

Find the zeros of x^2-20x+100=25

The zeros of x^2-20x+100=25 are x=15,x=5

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x^{2} - 20 x + 100 = 25

x = 15, x = 5

Solution steps

x^{2} - 20 x + 100 = 25

Move

25

to the left side

x^{2} - 20 x + 75 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 75}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot 75 = 10

x_{1, 2} = \frac{- ( - 20 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 10}{2 \cdot 1}

x = \frac{- ( - 20 ) + 10}{2 \cdot 1} : 15

x = \frac{- ( - 20 ) - 10}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

x = 15, x = 5

(3 x + 3)^{2} - 42 = - 39

4 x^{2} - 8 x

x, U = \frac{1}{2} k x^{2}

12 x^{2} - 10 x + 1 = 0

x^{2} - 29 x = 0

What are the solutions to the equation x^2-20x+100=25 ?
The solutions to the equation x^2-20x+100=25 are x=15,x=5
Find the zeros of x^2-20x+100=25
The zeros of x^2-20x+100=25 are x=15,x=5