What are the solutions to the equation r^2+6r+8=0 ?

The solutions to the equation r^2+6r+8=0 are r=-2,r=-4

Find the zeros of r^2+6r+8=0

The zeros of r^2+6r+8=0 are r=-2,r=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{2} + 6 r + 8 = 0

r = - 2, r = - 4

Solution steps

r^{2} + 6 r + 8 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 8 = 2

r_{1, 2} = \frac{- 6 \pm 2}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 6 + 2}{2 \cdot 1}, r_{2} = \frac{- 6 - 2}{2 \cdot 1}

r = \frac{- 6 + 2}{2 \cdot 1} : - 2

r = \frac{- 6 - 2}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

r = - 2, r = - 4

x, x^{2} + y^{2} = c

4 x^{2} + 7 x + 6 = 0

x^{2} - 4 x + 2

x^{2} + 7 x + 13 = 0

7 x^{2} - 13 x + 6 = 0

What are the solutions to the equation r^2+6r+8=0 ?
The solutions to the equation r^2+6r+8=0 are r=-2,r=-4
Find the zeros of r^2+6r+8=0
The zeros of r^2+6r+8=0 are r=-2,r=-4