What are the solutions to the equation 5(x-10)^2-33=-3 ?

The solutions to the equation 5(x-10)^2-33=-3 are x=sqrt(6)+10,x=-sqrt(6)+10

Find the zeros of 5(x-10)^2-33=-3

The zeros of 5(x-10)^2-33=-3 are x=sqrt(6)+10,x=-sqrt(6)+10

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5 (x - 10)^{2} - 33 = - 3

x = 6 + 10, x = - 6 + 10

Decimal Notation

x = 12.44948 \dots, x = 7.55051 \dots

Solution steps

5 (x - 10)^{2} - 33 = - 3

Move

33

to the right side

5 (x - 10)^{2} = 30

Divide both sides by

5

(x - 10)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 10 = 6 : x = 6 + 10

Solve

x - 10 = - 6 : x = - 6 + 10

The solutions to the quadratic equation are:

x = 6 + 10, x = - 6 + 10

r, v = \frac{π r ^{2} h}{3}

(4 x - 1)^{2} = 144

x^{2} + 30 x + 200 = 0

3 x^{2} - 7 x = 4 x - 8

3 x^{2} + 231 = - 54 x

What are the solutions to the equation 5(x-10)^2-33=-3 ?
The solutions to the equation 5(x-10)^2-33=-3 are x=sqrt(6)+10,x=-sqrt(6)+10
Find the zeros of 5(x-10)^2-33=-3
The zeros of 5(x-10)^2-33=-3 are x=sqrt(6)+10,x=-sqrt(6)+10