What are the solutions to the equation 6x+55=x^2 ?

The solutions to the equation 6x+55=x^2 are x=11,x=-5

Find the zeros of 6x+55=x^2

The zeros of 6x+55=x^2 are x=11,x=-5

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6 x + 55 = x^{2}

x = 11, x = - 5

Solution steps

6 x + 55 = x^{2}

Switch sides

x^{2} = 6 x + 55

Move

55

to the left side

x^{2} - 55 = 6 x

Move

6 x

to the left side

x^{2} - 55 - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 6 x - 55 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 55 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 55) = 16

x_{1, 2} = \frac{- ( - 6 ) \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 16}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 16}{2 \cdot 1}

x = \frac{- ( - 6 ) + 16}{2 \cdot 1} : 11

x = \frac{- ( - 6 ) - 16}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 11, x = - 5

- 2 x^{2} + 150 x + 1700 = 0

x^{2} + 6 x + 5

x^{2} + 6 x + 8 = 0

x, (x + y)^{3} = x^{3} + y^{3}

6 x^{2} + 125 = x^{2}

What are the solutions to the equation 6x+55=x^2 ?
The solutions to the equation 6x+55=x^2 are x=11,x=-5
Find the zeros of 6x+55=x^2
The zeros of 6x+55=x^2 are x=11,x=-5